6y^2+19y+15=(3y+5)(2y+3)

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Solution for 6y^2+19y+15=(3y+5)(2y+3) equation: 



6y^2+19y+15=(3y+5)(2y+3)

We move all terms to the left:

6y^2+19y+15-((3y+5)(2y+3))=0

We multiply parentheses ..

6y^2-((+6y^2+9y+10y+15))+19y+15=0



We calculate terms in parentheses: -((+6y^2+9y+10y+15)), so:

(+6y^2+9y+10y+15)

We get rid of parentheses

6y^2+9y+10y+15

We add all the numbers together, and all the variables

6y^2+19y+15

Back to the equation:

-(6y^2+19y+15)



We add all the numbers together, and all the variables

6y^2+19y-(6y^2+19y+15)+15=0

We get rid of parentheses

6y^2-6y^2+19y-19y-15+15=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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